3j^2-20j+12=0

Solution for 3j^2-20j+12=0 equation:

Simplifying
3j2 + -20j + 12 = 0

Reorder the terms:
12 + -20j + 3j2 = 0

Solving
12 + -20j + 3j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(2 + -3j)(6 + -1j) = 0

Subproblem 1
Set the factor '(2 + -3j)' equal to zero and attempt to solve:

Simplifying
2 + -3j = 0

Solving
2 + -3j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -3j = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -3j = 0 + -2
-3j = 0 + -2

Combine like terms: 0 + -2 = -2
-3j = -2

Divide each side by '-3'.
j = 0.6666666667

Simplifying
j = 0.6666666667
Subproblem 2
Set the factor '(6 + -1j)' equal to zero and attempt to solve:

Simplifying
6 + -1j = 0

Solving
6 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1j = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1j = 0 + -6
-1j = 0 + -6

Combine like terms: 0 + -6 = -6
-1j = -6

Divide each side by '-1'.
j = 6

Simplifying
j = 6
Solution
j = {0.6666666667, 6}